0.0013=2E-05x^2-0.0002x+0.0002

Solution for 0.0013=2E-05x^2-0.0002x+0.0002 equation:

0.0013=2-05E^2-0.0002E+0.0002

We move all terms to the left:

0.0013-(2-05E^2-0.0002E+0.0002)=0

We get rid of parentheses

05E^2+0.0002E-2-0.0002+0.0013=0

We add all the numbers together, and all the variables

05E^2+0.0002E-1.9989=0

a = 05; b = 0.0002; c = -1.9989;
Δ = b2-4ac
Δ = 0.00022-4·05·(-1.9989)
Δ = 39.97800004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0002)-\sqrt{39.97800004}}{2*05}=\frac{-0.0002-\sqrt{39.97800004}}{10}
$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0002)+\sqrt{39.97800004}}{2*05}=\frac{-0.0002+\sqrt{39.97800004}}{10}
$